document.write( "Question 959517: A woman is twice as old as her daughter. 5 years ago the sum of ages was 62. What are their present ages? \n" ); document.write( "
Algebra.Com's Answer #586481 by amarjeeth123(569)\"\" \"About 
You can put this solution on YOUR website!
Let the daughter's age be x.
\n" ); document.write( "Then the woman's age is 2x.
\n" ); document.write( "5 years ago their ages will be (x-5) and (2x-5) respectively.
\n" ); document.write( "(x-5)+(2x-5)=62
\n" ); document.write( "3x-10=62
\n" ); document.write( "3x=72
\n" ); document.write( "x=24
\n" ); document.write( "The daughter's age is 24 years.
\n" ); document.write( "The woman's age is 48 years.
\n" ); document.write( "
\n" ); document.write( "
\n" );