document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959484>Question 959484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you main the leading coefficient of the polynomial:\r<BR>\n" );
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document.write( "P(x)=A(x+1)^2(x-1)^3(x-2)\r<BR>\n" );
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document.write( "I know the Y-intercept is P(0)=-2 but what do I after that?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586470 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P has one real number factor and a few binomial factors; and each binomial factor has leading coefficient of 1.  The leading coefficient for P will simply be A.\r<BR>\n" );
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document.write( "You can try to fully multiply the right member and adjust into general form but the effort is unnecessary.\r<BR>\n" );
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document.write( "You want to FIND the value for A?<BR>\n" );
document.write( "You have P(0)=-2, so just substitute and equate.\r<BR>\n" );
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document.write( "You can solve this for A. </SPAN>\n" );
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