document.write( "Question 81850: A consultant traveled 10 hours to attend a meeting. The return trip took only 9 hours because the speed was 7 moles per hour faster. What was the consultant's speed each way?\r
\n" ); document.write( "\n" ); document.write( "Now, correct me if I am wrong, but wouldn't I also need a distance traveled in order to find the speed each way?
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Algebra.Com's Answer #58646 by Earlsdon(6294)\"\" \"About 
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Knowing the distance is not necessary to solve this problem.
\n" ); document.write( "Use the distance formula \"d+=+rt\"for each way.
\n" ); document.write( "\"d+=+r%5B1%5Dt%5B1%5D\" and
\n" ); document.write( "\"d+=+r%5B2%5Dt%5B2%5D\" Where r is the rate (speed) and t is the time of travel.
\n" ); document.write( "You know that the distance, d, is the same in both cases.
\n" ); document.write( "You also know that \"r%5B2%5D=r%5B1%5D%2B7\"
\n" ); document.write( "You know that \"t%5B1%5D+=+10\" and\"t%5B2%5D+=+9\"
\n" ); document.write( "Making the appropriate substitutions, you'll get:
\n" ); document.write( "\"d+=+r%5B1%5D%2A10\"
\n" ); document.write( "\"d+=+%28r%5B1%5D%2B7%29%2A9\"
\n" ); document.write( "Set these two equations equal to each other and solve for \"r%5B1%5D\"
\n" ); document.write( "\"r%5B1%5D%2A10+=+%28r%5B1%5D%2B7%29%2A9\" Simplify.
\n" ); document.write( "\"10r%5B1%5D+=+9r%5B1%5D%2B63\" Subtract \"9r%5B1%5D\" from both sides.
\n" ); document.write( "\"r%5B1%5D+=+63\"mph
\n" ); document.write( "\"r%5B2%5D+=+r%5B1%5D%2B7\"
\n" ); document.write( "\"r%5B2%5D+=+63%2B7\"
\n" ); document.write( "\"r%5B2%5D+=+70\"mph
\n" ); document.write( "Check:
\n" ); document.write( "\"63%2A10+=+630\"miles. This is the distance one-way.
\n" ); document.write( "\"70%2A9+=+630\"miles.
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