document.write( "Question 959458: solve for x:\r
\n" ); document.write( "\n" ); document.write( "log2(8x)-log2(x^2-1)=log2(3)
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Algebra.Com's Answer #586457 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%288x%29%29-log%282%2C%28x%5E2-1%29%29=log%282%2C%283%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%282%2C%288x%29%2F%28x%5E2-1%29%29=log%282%2C%283%29%29\"...if log same, then\r
\n" ); document.write( "\n" ); document.write( "\"8x%2F%28x%5E2-1%29=3\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=3%28x%5E2-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=3x%5E2-3\"\r
\n" ); document.write( "\n" ); document.write( "\"0=3x%5E2-8x-3\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2-9x%2Bx-3=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283x%5E2-9x%29%2B%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%28x-3%29%2B%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283x%2B1%29%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"%283x%2B1%29=0\"=>\"3x=-1\"=>\"x=-1%2F3\"(assuming a complex-valued logarithm)
\n" ); document.write( "\"%28x-3%29=0\"=>\"x=3\"
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