document.write( "Question 959417: A recent poll pertaining to educational reforms involved 634 men and 820 women. The margin of error is 3.6% for the male sample and 3.2% for the female sample. Find the level of confidence for the male portion of the poll and for the female portion of the poll. HINT: See Example 7. (Round your answers to one decimal place.)\r
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document.write( "a) male %\r
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document.write( "b) female %
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Algebra.Com's Answer #586450 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A recent poll pertaining to educational reforms involved 634 men and 820 women. The margin of error is 3.6% for the male sample and 3.2% for the female sample. Find the level of confidence for the male portion of the poll and for the female portion of the poll. HINT: See Example 7. (Round your answers to one decimal place.) \n" ); document.write( " a) male % \n" ); document.write( "ME = z*sqrt[pq/n] \n" ); document.write( "----- \n" ); document.write( "0.036 = z*sqrt[(1/2)(1/2)/634] \n" ); document.write( "0.036 = z(1/2)(1/25.18] \n" ); document.write( "z/2 = 25.18*0.036 \n" ); document.write( "z = 1.81 \n" ); document.write( "--- \n" ); document.write( "normalcdf(1.81,100) = 0.035 \n" ); document.write( "level of confidence = 2*3.5 = 7% \n" ); document.write( "------------------------------------ \n" ); document.write( " \n" ); document.write( "b) female % \n" ); document.write( "z*(1/2)[1/sqrt(820)] = 0.032 \n" ); document.write( "---- \n" ); document.write( "z*(1/2)[1/28.64] = 0.032 \n" ); document.write( "---- \n" ); document.write( "z = 0.032*2*28.64 = 1.84 \n" ); document.write( "---- \n" ); document.write( "normalcdf(1.84,100) = 0.033 \n" ); document.write( "level of confidence = 2*3.3% = 6.6% \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |