document.write( "Question 959420: I'm having trouble with this question: The mean of three numbers is 31. The second is 1 more than twice the first. The third is 4 less than 3 times the first. Find the numbers.\r
\n" ); document.write( "\n" ); document.write( "I put the equation x+2x+1+3x-4
\n" ); document.write( "The problem is that I don't know what to equal it to. I tried with 31, as that is the mean, but I checked it and it did not work. Can you please help me? Thank you.
\n" ); document.write( "

Algebra.Com's Answer #586438 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The mean of three numbers is \"31\".
\n" ); document.write( "\"%28x%2By%2Bz%29%2F3=31\"
\n" ); document.write( "\"x%2By%2Bz=31%2A3\"
\n" ); document.write( "\"x%2By%2Bz=93\"\r
\n" ); document.write( "\n" ); document.write( "if the second is \"1\" more than twice the first, we have
\n" ); document.write( "\"y=2x%2B1\"
\n" ); document.write( "if the third is \"4\" less than \"3\" times the first, we have
\n" ); document.write( "\"z=3x-4\"\r
\n" ); document.write( "\n" ); document.write( "substitute it in \"x%2By%2Bz=93\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2x%2B1%2B3x-4=93\"........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"6x-3=93\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=93%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=96\"\r
\n" ); document.write( "\n" ); document.write( "\"x=96%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=16%29\"\r
\n" ); document.write( "\n" ); document.write( "now find \"y\" and \"z\"\r
\n" ); document.write( "\n" ); document.write( "\"y=2x%2B1\"
\n" ); document.write( "\"y=2%2A16%2B1\"
\n" ); document.write( "\"highlight%28y=33%29\"\r
\n" ); document.write( "\n" ); document.write( "\"z=3x-4\"
\n" ); document.write( "\"z=3%2A16-4\"
\n" ); document.write( "\"z=48-4\"
\n" ); document.write( "\"highlight%28z=44%29\"
\n" ); document.write( "
\n" );