document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959420>Question 959420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having trouble with this question: The mean of three numbers is 31. The second is 1 more than twice the first. The third is 4 less than 3 times the first. Find the numbers.\r<BR>\n" );
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document.write( "I put the equation x+2x+1+3x-4<BR>\n" );
document.write( "The problem is that I don't know what to equal it to. I tried with 31, as that is the mean, but I checked it and it did not work. Can you please help me? Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586437 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x +2x+1 +3x-4) / 3 = 31<BR>\n" );
document.write( "here we have used the definition of the mean<BR>\n" );
document.write( "(x +2x+1 +3x-4 = 93<BR>\n" );
document.write( "multiply both sides of = by 3<BR>\n" );
document.write( "6x -3 = 93<BR>\n" );
document.write( "6x = 96<BR>\n" );
document.write( "x = 16<BR>\n" );
document.write( "the numbers are 16, 33, 44<BR>\n" );
document.write( "note that (16 +33 +44) / 3 = 31<BR>\n" );
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