document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959342>Question 959342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times one number plus a second number is 40,and the one number minus the second number is 4. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586395 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=first number: S=second number<BR>\n" );
document.write( "F-S=4<BR>\n" );
document.write( "F=S+4<BR>\n" );
document.write( "3F+S=40 Substitute for F<BR>\n" );
document.write( "3(S+4)+S=40<BR>\n" );
document.write( "3S+12+S=40<BR>\n" );
document.write( "4S=28<BR>\n" );
document.write( "S=7 ANSWER 1: The second number is 7.<BR>\n" );
document.write( "F=S+4=7+4=11 ANSWER 2: The first number is 11<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "3F+S=40<BR>\n" );
document.write( "3(11)+7=40<BR>\n" );
document.write( "33+7=40<BR>\n" );
document.write( "40=40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );