document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959333>Question 959333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From Glencoe Alg I 10-4 #4 word problem.  I have spent over a day with this one.  <BR>\n" );
document.write( "Firefighting. Firefighters calculate the flow rate of water out of a particular hydrant by the following formula: Flow rate = 26.9 x d^2 x sqrt P.  P is nozzle pressure and d is hose diameter. The combined flow rate of two hoses is 2430 gpm.  The diameter of each hose is 3 inches but the pressure of one hose is 4 times that of the other. What are the nozzle pressures of each hose?<BR>\n" );
document.write( "I have the answer key and it says 11.2 and 44.8 psi.  For the life of me, regardless of how I manipulate the formula, I cannot come up with this answer.Can you show me the setup of the formula? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586392 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem uses the following formula<BR>\n" );
document.write( "Flow rate = 26.9 x d^2 x sqrt P<BR>\n" );
document.write( "we have two hoses with d = 3 each and P and 4p for pressure, therefore we have the following formula<BR>\n" );
document.write( "(26.9 * 3^2 * sqrt(P)) + (26.9 * 3^2 * sqrt(4P)) = 2430<BR>\n" );
document.write( "(242.1*sqrt(P)) + (242.1 * sqrt(4P)) = 2430<BR>\n" );
document.write( "Note that sqrt(4P) = 2*sqrt(P) <BR>\n" );
document.write( "(242.1 * sqrt(P)) + (484.2 * sqrt(P)) = 2430<BR>\n" );
document.write( "726.3 * sqrt(P) = 2430<BR>\n" );
document.write( "sqrt(P) = 3.345724907<BR>\n" );
document.write( "square both sides of =<BR>\n" );
document.write( "P = 11.193875154 approx 11.2<BR>\n" );
document.write( "The two pressure values are 11.2 psi and 44.8 psi<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );