document.write( "Question 959335: Three more than the square root of the sum of 3 consecutive odd numbers is 12. Find the three numbers. \n" ); document.write( "

Algebra.Com's Answer #586391 by macston(5194) $\"\"$ $\"About$

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n,n+2,and n+4 are consecutive odd integers
\n" ); document.write( " $\"sqrt%28n%2B%28n%2B2%29%2B%28n%2B4%29%29%2B3=12\"$ Subtract 3 from each side.
\n" ); document.write( " $\"sqrt%283n%2B6%29=9\"$ Square each side.
\n" ); document.write( " $\"3n%2B6=81\"$ Subtract 6 from each side.
\n" ); document.write( " $\"3n=75\"$ Divide each side by 3.
\n" ); document.write( " $\"n=25\"$ ANSWER 1: The first odd number is 25
\n" ); document.write( " $\"n%2B2=25%2B2\"$ = $\"27\"$ ANSWER 2: The second number is 27.
\n" ); document.write( " $\"N%2B4=25%2B4\"$ = $\"29\"$ ANSWER 3: The third number is 29.
\n" ); document.write( "CHECK:
\n" ); document.write( " $\"sqrt%2825%2B27%2B29%29%2B3=12\"$
\n" ); document.write( " $\"sqrt%2881%29%2B3=12\"$
\n" ); document.write( " $\"9%2B3=12\"$
\n" ); document.write( " $\"12=12\"$ \n" ); document.write( "

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