document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81848>Question 81848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second.\r<BR>\n" );
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document.write( "I don't even know how to sow my work to do this or even where to start.  I have been muliplying 3's and 5's like a crazy lady, but there are so many numbers in this world!!  hehehe\r<BR>\n" );
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document.write( "So far, I have only managed to guess at an expression for it as 5a - 3b = 12 which might make sense, but I don't think this is how they want you to figure it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58638 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first odd integer be x.<BR>\n" );
document.write( "The next consecutive odd integer is x+2.<BR>\n" );
document.write( "5x = 3(x+2)+12  Five times the first (5x) is (=) 12 more (+12) than three times the second (3(x+2)) <BR>\n" );
document.write( "5x = 3x+6 + 12<BR>\n" );
document.write( "5x = 3x + 18 Subtract 3x from both sides.<BR>\n" );
document.write( "2x = 18 Divide both sides by 2.<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "x+2 = 11 </SPAN>\n" );
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