document.write( "Question 81822: Solve the system by addition or substitution.
\n" );
document.write( " –8x + 2y = 8
\n" );
document.write( " y = 4 + 4x
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #58636 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given the equation set: \n" ); document.write( ". \n" ); document.write( " –8x + 2y = 8 \n" ); document.write( " y = 4 + 4x \n" ); document.write( ". \n" ); document.write( "Solve by addition or substitution. \n" ); document.write( ". \n" ); document.write( "First by addition: \n" ); document.write( ". \n" ); document.write( "Rearrange the bottom equation so that it is in the same arrangement as the top equation. \n" ); document.write( "So get the bottom equation so the terms containing x and y are on the left side and the \n" ); document.write( "constants are on the right side. Do it using the following process: \n" ); document.write( ". \n" ); document.write( "y = 4 + 4x \n" ); document.write( ". \n" ); document.write( "eliminate the 4x on the right side by subtracting 4x from both sides to get: \n" ); document.write( ". \n" ); document.write( "-4x + y = 4 \n" ); document.write( ". \n" ); document.write( "This is in the form of the original top equation. So now the equation set is: \n" ); document.write( ". \n" ); document.write( "-8x + 2y = 8 \n" ); document.write( "-4x + y = 0 \n" ); document.write( ". \n" ); document.write( "If you now multiply both sides of the bottom equation by -2 the equation set becomes: \n" ); document.write( ". \n" ); document.write( "-8x + 2y = 8 \n" ); document.write( "+8x - 2y = 0 \n" ); document.write( ". \n" ); document.write( "Now you can add the two equations. But notice that when you do that the result is that \n" ); document.write( "both the x and the y terms on the left side cancel each other and the result is: \n" ); document.write( ". \n" ); document.write( "0 = 0 \n" ); document.write( ". \n" ); document.write( "More significantly, look at what we did to the bottom equation. We rearranged it and then \n" ); document.write( "multiplied both sides by a common number. Suppose that instead of multiplying the rearranged \n" ); document.write( "bottom equation by -2 we had multiplied it by +2. The result would have been that it \n" ); document.write( "would become -8x + 2y = 8 and the equation set would then be: \n" ); document.write( ". \n" ); document.write( "-8x + 2y = 8 and \n" ); document.write( "-8x + 2y = 8 \n" ); document.write( ". \n" ); document.write( "This shows that the bottom equation is actually the same as the top equation. And that \n" ); document.write( "means that any solution of the top equation is also a solution to the bottom equation. \n" ); document.write( "So for the given set of equations, there are an infinite number of common solutions, \n" ); document.write( "not just one. Any solution for one of the equations is common with the other equation \n" ); document.write( "because both equations are the same. \n" ); document.write( ". \n" ); document.write( "If you try to solve this by substitution, you can notice that the original bottom \n" ); document.write( "equation is already solved for y. So you can substitute the right side of the bottom \n" ); document.write( "equation for y in the top equation. When you do that substitution the top equation \n" ); document.write( "becomes: \n" ); document.write( ". \n" ); document.write( "-8x + 2(4 + 4x) = 8 \n" ); document.write( ". \n" ); document.write( "Do the distributed multiplication on the left side by multiplying 2 times each of the \n" ); document.write( "terms in parentheses to get: \n" ); document.write( ". \n" ); document.write( "-8x + 8 + 8x = 8 \n" ); document.write( ". \n" ); document.write( "Notice again how the two terms containing x cancel and the equation becomes: \n" ); document.write( ". \n" ); document.write( "8 = 8 \n" ); document.write( ". \n" ); document.write( "And subtracting 8 from both sides again results in 0 = 0. This again is a clue that something \n" ); document.write( "is amiss and that the two equations have to be identical for both sides to become \n" ); document.write( "0 = 0. Again the conclusion is that if the equations are identical (or can be made so \n" ); document.write( "with some permissible algebraic manipulations) then every solution of one is a solution \n" ); document.write( "of the other ... and there are an infinite number of common solutions. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand this \"tricky\" problem. \n" ); document.write( " |