document.write( "Question 959269: A jet plane flying with the wind flew 2200 km in 4 hours. Flying against the wind, the plane could fly only 1820 km in the same amount of time. Find:
\n" ); document.write( "a) The rate of the plane in calm air and,
\n" ); document.write( "b) The rate of the wind
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Algebra.Com's Answer #586354 by macston(5194)\"\" \"About 
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R=rate of plane; W=rate of wind
\n" ); document.write( "R+W=2200km/4hrs=550km/hr
\n" ); document.write( "R-W=1820km/4hrs=455 km/hr
\n" ); document.write( "R-W=455km/hr Add W to each side.
\n" ); document.write( "R=455km/hr+W
\n" ); document.write( "R+W=550km/hr Substitute for R.
\n" ); document.write( "455km/hr+W+W=550km/hr Subtract 455km/hr from each side.
\n" ); document.write( "2W=95km/hr Divide each side by 2.
\n" ); document.write( "W=47.5 km/hr ANSWER B): Speed of the wind was 47.5 km/hr.
\n" ); document.write( "R=455km/hr+W=455km/hr+47.5km/hr=502.5km/hr
\n" ); document.write( "ANSWER A): The rate of the plane in calm air was 502.5 km/hr.
\n" ); document.write( "CHECK:
\n" ); document.write( "2200km/(502.5km/hr+47.5km/hr)=1820km/(502.5km/hr-47.5km/hr)
\n" ); document.write( "2200km/(550km/hr)=1820km/(455km/hr)
\n" ); document.write( "4hrs=4hrs
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