document.write( "Question 959249: Explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equation y=2/3x-4 passing through the point (-2,-5). Write your answer in standard form. \n" ); document.write( "
Algebra.Com's Answer #586341 by macston(5194)\"\" \"About 
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The equation is given in slope intercept form:
\n" ); document.write( "y=mx+b where m is the slope. Parallel lines have the same slope.
\n" ); document.write( "PART 1:
\n" ); document.write( "The equation will be y=2/3x-b Use point(-2,-5) to find b.
\n" ); document.write( "-5=(2/3)(-2)+b
\n" ); document.write( "-5=(-4/3)+b Add 4/3 to each side.
\n" ); document.write( "-15/3+4/3=b
\n" ); document.write( "-11/3=b So the parallel line in slope intercept form the equation is:
\n" ); document.write( "y=2/3x-11/3
\n" ); document.write( "The parallel line in standard form:
\n" ); document.write( "2/3x-y=11/3
\n" ); document.write( "PART 2:
\n" ); document.write( "Perpendicular line has slope=negative reciprocal=-3/2
\n" ); document.write( "The equation therefore will be: y=(-3/2)x+b Again use given point to find b.
\n" ); document.write( "-5=(-3/2)(-2)+b
\n" ); document.write( "-5=3+b Subtract 3 from each side.
\n" ); document.write( "-8=b
\n" ); document.write( "The perpendicular line in slope intercept form:
\n" ); document.write( "y=(-3/2)x-8
\n" ); document.write( "And in standard form:
\n" ); document.write( "(3/2)x+y=-8\r
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