document.write( "Question 959238: Please help me solve this question: ABCD is a square with 8 inch sides. Point E is the midpoint of side AB and point F is the midpoint of side BC. What is the area of the triangle DEF?
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Algebra.Com's Answer #586330 by macston(5194) $\"\"$ $\"About$

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Triangles AED and CDF are right triangles with legs 4 in and 8 in,
\n" ); document.write( "so each has area (1/2)(4in)(8in)=16 square inches.
\n" ); document.write( "The small triangle EBF is a isosceles right triangle with legs 4 inches,
\n" ); document.write( "so has an area of (1/2)(4in)(4in)=8 square inches.
\n" ); document.write( "The total area of the square is (8in)(8in)=64 square inches.
\n" ); document.write( "The area of square square ABCD is the sum of the four triangles,
\n" ); document.write( "so the area of triangle DEF = Area ABCD - Area AED - Area CDF - Area EBF
\n" ); document.write( "Area DEF= $\"64in%5E2-16in%5E2-16in%5E2-8in%5E2=64in%5E2-40in%5E2\"$ = $\"24in%5E2\"$
\n" ); document.write( "ANSWER: The area of triangle DEF is 24 square inches.
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