document.write( "Question 959228: You have 20 coins some dimes and some nickels and you need to make $1.40 but you need more dimes than nickels \n" ); document.write( "
Algebra.Com's Answer #586322 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=dimes; N=nickels
\n" ); document.write( "D+N=20
\n" ); document.write( "D=20-N
\n" ); document.write( "$0.10D+$0.05N=$1.40 Substitute for D
\n" ); document.write( "$0.10(20-N)+$0.05N=$1.40
\n" ); document.write( "$2.00-$0.10N+$0.05N=$1.40 Subtract $2.00 from each side.
\n" ); document.write( "-$0.05N=-$0.60 Divide each side by $0.05
\n" ); document.write( "N=12 ANSWER 1: There are 12 nickels
\n" ); document.write( "D=20-N=20-12=8 ANSWER 2: There are 8 dimes.
\n" ); document.write( "CHECK:
\n" ); document.write( "$0.10D+$0.05N=$1.40
\n" ); document.write( "$0.10(8)+$0.05(12)=$1.40
\n" ); document.write( "$0.80+$0.60=$1.40
\n" ); document.write( "$1.40=$1.40
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