document.write( "Question 958868: A restaurant has a weekly ad in a local newspaper that is 2 inches wide and 4 inches high and cost $36.75 per week. The cost of each ad is based on its area. If the owner of the restaurant decides to double the width and height of the ad, how much will the new ad cost? \n" ); document.write( "
Algebra.Com's Answer #586314 by macston(5194)\"\" \"About 
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A=area; L=length; W=width
\n" ); document.write( "\"A=LW\"
\n" ); document.write( "Double width: Multiply each side by 2
\n" ); document.write( "\"2A=L2W\"
\n" ); document.write( "Double length: Multiply each side by 2
\n" ); document.write( "\"4A=2L2W\"
\n" ); document.write( "Doubling length and with multiplies area (and thus cost) by 4:
\n" ); document.write( "4($36.75)=$147.00 ANSWER: The new ad will cost $147.00.
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