document.write( "Question 959205: The perimeter of a rectangular field is110 meters.and the area of the field is 750square meters
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document.write( "Find the diamention of the field?The perimeter of a rectangular field is110 meters.and the area of the field is 750square meters
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document.write( "Find the diamention of the field? \n" );
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Algebra.Com's Answer #586299 by stanbon(75887) ![]() You can put this solution on YOUR website! The perimeter of a rectangular field is 110 meters.and the area of the field is 750 square meters \n" ); document.write( "Find the dimentions of the field? \n" ); document.write( "------ \n" ); document.write( "Equations: \n" ); document.write( "L + W = 55 meters \n" ); document.write( "LW = 750 meters \n" ); document.write( "----- \n" ); document.write( "Substitute for \"L\" and solve for \"W\":: \n" ); document.write( "(55-W)W = 750 \n" ); document.write( "-W^2 + 55W = 750 \n" ); document.write( "---- \n" ); document.write( "W^2 - 55W + 750 = 0 \n" ); document.write( "Factor:: \n" ); document.write( "(W-25)(W-30) = 0 \n" ); document.write( "--- \n" ); document.write( "If Width = 25, Length = 30 \n" ); document.write( "If Width = 30, Length = 25 \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |