document.write( "Question 959154: a) The perimeter of a rectangular field is 120 meters. Its length is 10 meters more than its width. Find the length and width of this rectangle?\r
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document.write( "b) Going for a long trip, Joshua drove for 3 hours and had lunch. After lunch he drove for 4 more hours at a speed that is 10 km/h more than before lunch. The total trip was 600 km.
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document.write( "i. What was his speed before lunch?
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document.write( "ii. What distance did he drive after lunch?\r
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document.write( "can i have the solution as well. Thanks\r
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Algebra.Com's Answer #586298 by rothauserc(4718) You can put this solution on YOUR website! a) Perimeter(P) = 2l +2w where l is length and w is width \n" ); document.write( "we are given l = w +10, therefore \n" ); document.write( "2(w+10) + 2w = 120 \n" ); document.write( "2w +20 +2w = 120 \n" ); document.write( "4w = 100 \n" ); document.write( "w = 25 and \n" ); document.write( "length is 35 meters and width is 25 meters \n" ); document.write( "b) we use the formula rate * time = distance, let \n" ); document.write( "r be Joshua's rate before lunch and r+10 is his rate after lunch, therefore \n" ); document.write( "3r + 4(r+10) = 600 \n" ); document.write( "3r +4r +40 = 600 \n" ); document.write( "7r = 560 \n" ); document.write( "r = 80 \n" ); document.write( "i) Joshua's speed before lunch is 80 km per hour \n" ); document.write( "ii) after lunch, \n" ); document.write( "4(r+10) = 4(80+10) = 360 km \n" ); document.write( "Joshua travels 360 km after lunch\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |