document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959195>Question 959195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please my problem is to express this in logarithm form: <BR>\n" );
document.write( "1 1/4=x<BR>\n" );
document.write( "And my answer is log base one of x is equals to one quarter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586288 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> not sure what this represents.\r<BR>\n" );
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document.write( "is this 1 and 1/4 = x or is this 1^(1/4) = x\r<BR>\n" );
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document.write( "1 and 1/4 is equal to 1.25 which doesn't seem to be a logarithmic type of problem.\r<BR>\n" );
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document.write( "1^(1/4) is equal to 1 raised to the power of (1/4) which can be considered to be a logarithmic type problem.\r<BR>\n" );
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document.write( "the exponential form and the logarithmic form go hand in hand based on the following definition of logs.\r<BR>\n" );
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document.write( "log(b,x) = y if and only if b^y = x\r<BR>\n" );
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document.write( "log(b,x) means log of x to the base of b.\r<BR>\n" );
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document.write( "b^y means base of b raised to the power of y.\r<BR>\n" );
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document.write( "i will assume you mean 1^(1/4) = x\r<BR>\n" );
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document.write( "by the basic definition of logs, this is true if and only if log(1,x) = 1/4.\r<BR>\n" );
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document.write( "that means log of x to the base of 1 is equal to 1/4.\r<BR>\n" );
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document.write( "your answer is:\r<BR>\n" );
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document.write( "log base one of x is equals to one quarter.\r<BR>\n" );
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document.write( "that looks like the same as my answer, so i would say you did good.\r<BR>\n" );
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