document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956472>Question 956472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a hula hoop is hung by a string at a height of 12 feet. Bruce is currently lying on his back and is lying 9 feet away from the hula hoop. If he is to throw the basketball through the hula hoop, what angle must he throw the ball at? How would I set this up? Thanks:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586268 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two legs are in a ratio of 9:12=3:4, which means this is a 3-4-5 triangle.<BR>\n" );
document.write( "Bruce is on the shorter leg, so he would be at the larger acute angle of 53 degrees. <BR>\n" );
document.write( "ANSWER: He would throw the ball at a 53 degree angle.<BR>\n" );
document.write( "If you don't know these angles, find the hypotenuse (5*3=15 feet)<BR>\n" );
document.write( "so arcsin(opp/hyp)=arcsin(12/15)=53 degrees.  </SPAN>\n" );
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