document.write( "Question 959039: A college professor has purchased a new bicycle for commuting to class. This bicycle had a purchase price of $600 and depreciates at a constant rate of $55 a year. What is the bicycle’s value after 3.5 years? How long before the bicycle is worth zero?
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Algebra.Com's Answer #586170 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+n+\"$ = number of years after purchase
\n" ); document.write( "Let $\"+V+\"$ = the bike's current value
\n" ); document.write( " $\"+V+=+600+-+55n+\"$
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\n" ); document.write( " $\"+V+=+600+-+55%2A3.5+\"$
\n" ); document.write( " $\"+V+=+600+-+192.5+\"$
\n" ); document.write( " $\"+V+=+407.5+\"$
\n" ); document.write( "After 3.5 years, the bicycle is worth $407.50
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\n" ); document.write( " $\"+0+=+600+-+55n+\"$
\n" ); document.write( " $\"+55n+=+600+\"$
\n" ); document.write( " $\"+n+=+10.91+\"$
\n" ); document.write( "In about 10 years and 11 months,
\n" ); document.write( "the bike will be worth zero
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