document.write( "Question 959037: Log2 (x+5)-log2(2x-1)=5 \n" ); document.write( "
Algebra.Com's Answer #586153 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"log%282+%2C%28x%2B5%29%29-log%282%2C%282x-1%29%29=5\"\r
\n" ); document.write( "\n" ); document.write( "\"log%282+%2C%28x%2B5%29%2F%282x-1%29%29=5\"....change the base to base \"10\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x%2B5%29%2F%282x-1%29%29%2Flog%282%29=5\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x%2B5%29%2F%282x-1%29%29=5log%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x%2B5%29%2F%282x-1%29%29=log%282%5E5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x%2B5%29%2F%282x-1%29%29=log%2832%29\"........if log same, then\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%2F%282x-1%29=32\".........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5=32%282x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5=64x-32\"\r
\n" ); document.write( "\n" ); document.write( "\"32%2B5=64x-x\"\r
\n" ); document.write( "\n" ); document.write( "\"37=63x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=37%2F63\"\r
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