document.write( "Question 959030: Log2 52-log2x =2 \n" ); document.write( "

Algebra.Com's Answer #586136 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"log%282%2C52%29-log%282%2Cx%29+=2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"log%282%2C52%2Fx%29+=2\"$ ...........change the base\r
\n" ); document.write( "\n" ); document.write( " $\"log%2852%2Fx%29%2Flog%282%29+=2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"log%2852%2Fx%29+=2log%282%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"log%2852%2Fx%29+=log%282%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"log%2852%2Fx%29+=log%284%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"52%2Fx+=4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"52+=4x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=52%2F4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=13\"$ \r
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