document.write( "Question 958982: three men A B C working together can do a job in 6 hrs less time than A alone, in 1 hr less time than B alone and in one half the time needed by C when working alone. then A and B together can do a job in ____ minutes. \n" ); document.write( "
Algebra.Com's Answer #586085 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! three men A B C working together can do a job in 6 hrs less time than A alone, in 1 hr less time than B alone and in one half the time needed by C when working alone. then A and B together can do a job in. \n" ); document.write( " \r\n" ); document.write( "Let x = the number of hours it takes A to do 1 job working alone.\r\n" ); document.write( "Let y = the number of hours it takes B to do 1 job working alone.\r\n" ); document.write( "Let z = the number of hours it takes C to do 1 job working alone.\r\n" ); document.write( "Let t = the number of hours it takes A,B, and C to do 1 job working together.\r\n" ); document.write( "\r\n" ); document.write( "Then\r\n" ); document.write( " \n" ); document.write( "three men A B C working together can do a job in 6 hrs less time than A alone, \n" ); document.write( " \r\n" ); document.write( " t = x - 6\r\n" ); document.write( "(1) x = t + 6\r\n" ); document.write( " \n" ); document.write( "in 1 hr less time than B alone \n" ); document.write( " \r\n" ); document.write( " t = y - 1\r\n" ); document.write( "(2) y = t + 1\r\n" ); document.write( " \n" ); document.write( "and in one half the time needed by C when working alone. \n" ); document.write( " \r\n" ); document.write( " t = \n" ); document.write( "A and B together can do a job in ____ hours. \n" ); document.write( " \r\n" ); document.write( "A's working rate =\n" ); document.write( " |