document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958954>Question 958954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is five less than a second number. Five times the first is eight more than two times the second. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586060 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first number=S-5; S=second number<BR>\n" );
document.write( "5F=2S+8 Substitute for F.<BR>\n" );
document.write( "5(S-5)=2S+8<BR>\n" );
document.write( "5S-25=2S+8 Add 25 to each side.<BR>\n" );
document.write( "5S=2S+33 Subtract 2s from each side.<BR>\n" );
document.write( "3S=33 Divide each side by 3<BR>\n" );
document.write( "S=11 ANSWER 1: The second number is 11.<BR>\n" );
document.write( "F=S-5=11-5=6 ANSWER 2: The first number is 6.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "5F=2S+8<BR>\n" );
document.write( "5(6)=2(11)+8<BR>\n" );
document.write( "30=30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );