document.write( "Question 958894: e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me? \n" ); document.write( "

Algebra.Com's Answer #586044 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me?
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 ---- Exponential form
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document.write( " --------- Converting log 100 to 2
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document.write( "ln 2 = 2x + 1 ------ Logarithmic form
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document.write( "    0.693147 = 2x + 1
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document.write( "0.693147 – 1 = 2x
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document.write( "  - 0.306853 = 2x
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document.write( ", or  \n" );
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