document.write( "Question 958882: find the largest area possible for a right triangle whose hypotenuse is 5 inches long \n" ); document.write( "
Algebra.Com's Answer #586031 by Edwin McCravy(20054) $\"\"$ $\"About$
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document.write( "Let the area be y.\r\n" );
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document.write( "Set y' equal to 0 to find relative extrema:\r\n" );
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document.write( "Square both sides:\r\n" );
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document.write( "Multiply both sides by the denominator on the right\r\n" );
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document.write( "Take positive square roots of both sides:\r\n" );
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document.write( "Take positive square roots of both sides:\r\n" );
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document.write( "Rationalize the denominator:\r\n" );
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document.write( "So the base is \r\n" );
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document.write( "We find the height but substituting in\r\n" );
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document.write( "height = \r\n" );
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document.write( "height = \r\n" );
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document.write( "height = \r\n" );
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document.write( "height = \r\n" );
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document.write( "height = \r\n" );
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document.write( "height = \r\n" );
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document.write( "height = \r\n" );
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document.write( "So the dimensions of the right triangle with maximum area has\r\n" );
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document.write( "base and height both equal to  \r\n" );
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document.write( "which is an isosceles right triangle.\r\n" );
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document.write( "Its area is found by substituting  into:\r\n" );
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document.write( "The maximum area is  or  square inches.\r\n" );
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document.write( "The triangle with maximum area looks like this:\r\n" );
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document.write( "Edwin
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