document.write( "Question 958894: e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me? \n" ); document.write( "
Algebra.Com's Answer #586028 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"e%5E%282x%2B1%29+=+log%2810%2C100%29\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%282x%2B1%29+=+log%2810%2C10%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%282x%2B1%29+=+2log%2810%2C10%29\".............\"log%2810%2C10%29=1\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%282x%2B1%29+=+2\"........take log of both sides\r
\n" ); document.write( "\n" ); document.write( "\"log%28e%5E%282x%2B1%29+%29=+log%28%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B1%29+log%28%28e%29%29=+log%28%282%29%29\"......\"log%28e%29=1\"\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B1%29%2A1=+log%28%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B1=+log%28%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2x=+log%28%282%29%29-1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+%28log%28%282%29%29-1%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+%281%2F2%29%28log%28%282%29%29-1%29\"
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