document.write( "Question 81772: Printing press A can print an order in 7hours. If printing press B is used along with press A, the job can be completed in 5hr. How long would it take printing press B to print the job by itself? \n" ); document.write( "
Algebra.Com's Answer #58601 by dolly(163)\"\" \"About 
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Time taken by press A = 7 hrs.
\n" ); document.write( "So work done in 1 hr = 1/7 part\r
\n" ); document.write( "\n" ); document.write( "Let the time taken by press B = x hrs
\n" ); document.write( "So work done in 1 hr = 1/x part\r
\n" ); document.write( "\n" ); document.write( "Together work done in 1 hr = 1/7 + 1/x\r
\n" ); document.write( "\n" ); document.write( " = (x + 7)/7x\r
\n" ); document.write( "\n" ); document.write( "Given they complete in 5 hrs.
\n" ); document.write( "==> they complete 1/5 part in 1 hr\r
\n" ); document.write( "\n" ); document.write( "So (x + 7)/7x = 1/5\r
\n" ); document.write( "\n" ); document.write( "==> 5(x+7) = 7x\r
\n" ); document.write( "\n" ); document.write( "==> 5x + 35 = 7x\r
\n" ); document.write( "\n" ); document.write( "==> 35 = 7x - 5x
\n" ); document.write( "==> 35 = 2x
\n" ); document.write( "==> 35/2 = x
\n" ); document.write( "==> 17.5 = x\r
\n" ); document.write( "\n" ); document.write( "Thus B takes 17.5 hrs to complete all by itself
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