document.write( "Question 958740: How many ounces of chocolate tha tis 60% coca should be mixed with 4 oz of chocolate that is 80% to produce a mixture that is75% cocoa? \n" ); document.write( "

Algebra.Com's Answer #585983 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = ounces of 60% chocolate needed
\n" ); document.write( " $\"+.6x+\"$ = ounces of cocoa in 60% mixture
\n" ); document.write( " $\"+.8%2A4+=+3.2+\"$ ounces in 80% chocolate
\n" ); document.write( "-----------------
\n" ); document.write( " $\"+%28+.6x+%2B+3.2+%29+%2F+%28+x+%2B+4+%29+=+.75+\"$
\n" ); document.write( " $\"+.6x+%2B+3.2+=+.75%2A%28+x+%2B+4+%29+\"$
\n" ); document.write( " $\"+.6x+%2B+3.2++=+.75x+%2B+3+\"$
\n" ); document.write( " $\"+.15x+=+.2+\"$
\n" ); document.write( " $\"+x+=+1.333+\"$
\n" ); document.write( "1.333 ounces of 60% chocolate are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.6%2A1.333+%2B+3.2+%29+%2F+%28+1.333+%2B+4+%29+=+.75+\"$
\n" ); document.write( " $\"+%28+.8+%2B+3.2+%29+%2F+%28+5.333+%29+=+.75+\"$
\n" ); document.write( " $\"+4+%2F+%28+16%2F3+%29+=+3%2F4+\"$
\n" ); document.write( " $\"+%28+3%2F16+%29%2A4+=+12%2F16+\"$
\n" ); document.write( " $\"+12%2F16+=+12%2F16+\"$
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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