document.write( "Question 958726: If Angle A is 20 degrees larger than angle B and angle C is half the sum of angle A and B, what do the angles measure? \n" ); document.write( "
Algebra.Com's Answer #585937 by mukul76(5)\"\" \"About 
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Let the angle B be x.
\n" ); document.write( "As per the problem angle A=x+20,
\n" ); document.write( "And angle C=x+x+20/2
\n" ); document.write( "A+B+C=180°(angle sum property of ∆)
\n" ); document.write( "x+20+x+(2x+20/2)=180°
\n" ); document.write( "After solving left hand side we get 4x+40+2x+20. 6x+60
\n" ); document.write( " ----------- = ------=180°
\n" ); document.write( " 2. 2
\n" ); document.write( "6x+60=180*2
\n" ); document.write( "6x+60=360
\n" ); document.write( "6x=360-60
\n" ); document.write( "6x=300
\n" ); document.write( "x=300/6
\n" ); document.write( "x=50°
\n" ); document.write( "Angle A=x+20=50+20=70°
\n" ); document.write( "Angle B=x=50°
\n" ); document.write( "Angle C=x+x+20/2=(70+50)/2=120/2=60°
\n" ); document.write( "Therefore 70+50+60=180°
\n" ); document.write( "Hence proved.
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