document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958703>Question 958703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has an angle of 0.75 rads, and an opposite side of 47 meters. Find the lengths of the remaining side if possible.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585917 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one angle and the opposite side is not enough to get a particular triangle.\r<BR>\n" );
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document.write( "you need at least 2 angles and 1 side opposite one of the angles.\r<BR>\n" );
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document.write( "then you can use the law of sines to find the length of the other sides.\r<BR>\n" );
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document.write( "you need at least 2 sides and 1 angle between them.\r<BR>\n" );
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document.write( "then you can use the law of cosines to find the third side and the other angles.\r<BR>\n" );
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document.write( "the attached diagram shows at least 3 triangles that have the same angle with the same length of side opposite it.\r<BR>\n" );
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document.write( "there are many others.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2015/032601.jpg\" alt=\"$$$\" </>\r<BR>\n" );
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document.write( "you would use the law of sines with these triangles to find the other angles and the length of the other sides.\r<BR>\n" );
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document.write( "the law of sines is:\r<BR>\n" );
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document.write( "a/sin(A) = b/sin(B) = c/sin(C).\r<BR>\n" );
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document.write( "a is the side opposite angle A.<BR>\n" );
document.write( "b is the side opposite angle B.<BR>\n" );
document.write( "c is the side opposite angle C.\r<BR>\n" );
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document.write( "With 2 angles and the side opposite one of them, you can find the other two angles and the length of the other two sides easily.\r<BR>\n" );
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document.write( "In the middle diagram, where the points of the triangle are labeled:\r<BR>\n" );
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document.write( "side a would be side BC which is opposite angle A.<BR>\n" );
document.write( "side b would be side AC which is opposite angle B.<BR>\n" );
document.write( "side c would be side AB which is opposite angle C.\r<BR>\n" );
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document.write( "if you have the length of 2 sides and the measure of the angle between them, you can use the law of cosines.\r<BR>\n" );
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document.write( "the law of cosines is:\r<BR>\n" );
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document.write( "c^2 = a^2 + b^2 - 2 * a * b * cos(C).<BR>\n" );
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