document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958653>Question 958653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> e^(2x+1)= log1000 i'm trying to convert to logarithmic form, can you please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585881 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> e^(2x+1)= log1000 i'm trying to convert to logarithmic form, can you please help me?<BR>\n" );
document.write( "log10000=3<BR>\n" );
document.write( "e^(2x+1)=3<BR>\n" );
document.write( "(2x+1)lne=ln3<BR>\n" );
document.write( "lne=1l<BR>\n" );
document.write( "2x+1=ln3<BR>\n" );
document.write( "2x=ln3-1<BR>\n" );
document.write( "x=(ln3-1)/2&#8776;0.0493 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );