document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958635>Question 958635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 is a factor of half of me my digits add up to 4 I am greater than 30 less than 100 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585868 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two clues that lead you to the answer are: \"my digits add up to 4\" and \"greater than 30\". Why? Because it rules out numbers beginning with 1 or 2 are out, any combination beginning with 1 or 2 would be less than 30.<BR>\n" );
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document.write( "Numbers beginning with 3 work, and if we look at the other clue \"my digits add up to 4\" you can see that 31 would be an option, but 5 is not a factor of 15.5.<BR>\n" );
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document.write( "*We also have 40. It is greater than 30, the two digits add up to 4+0= 4, *<BR>\n" );
document.write( "*and the factors *of 40 are 2*2*2*5, so 5 is a factor.                    *<BR>\n" );
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