document.write( "Question 958599: I dont think I got this question right but it would help if a tutor would check it and tell me what I did wrong if its wrong. Problem:
\n" ); document.write( "One of two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle.
\n" ); document.write( "x+y= 90
\n" ); document.write( "y= 30+3x
\n" ); document.write( "3x+30=90
\n" ); document.write( " -30 -30
\n" ); document.write( "3x=60
\n" ); document.write( "3 3
\n" ); document.write( "x=20
\n" ); document.write( "x= 20
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #585832 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "two angles (\"alpha\"° and \"beta\"°) are Complementary Angles if they add up to \"90\"°\r
\n" ); document.write( "\n" ); document.write( "so, \"alpha%2Bbeta=90\"°\r
\n" ); document.write( "\n" ); document.write( "given: one of two complementary angles (let's say \"alpha\") measures \"30\"° \"+more\" than \"three\"\"+times\" the other (let's say \"beta\"°)\r
\n" ); document.write( "\n" ); document.write( "so, we have that \"alpha=3beta%2B30\"° => substitute it in \"alpha%2Bbeta=90\"°\r
\n" ); document.write( "\n" ); document.write( "\"3beta%2B30%2Bbeta=90\"°........solve for \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"4beta=90-30\"°\r
\n" ); document.write( "\n" ); document.write( "\"4beta=60\"°\r
\n" ); document.write( "\n" ); document.write( "\"beta=60%2F4\"°\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28beta=15%29\"°\r
\n" ); document.write( "\n" ); document.write( "now find \"alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=3beta%2B30\"°\r
\n" ); document.write( "\n" ); document.write( "\"alpha=3%2A15%2B30\"°\r
\n" ); document.write( "\n" ); document.write( "\"alpha=45%2B30\"°\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28alpha=75%29\"°\r
\n" ); document.write( "\n" ); document.write( "
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