document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81737>Question 81737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two numbers is 47.  The second is 1 less than 3 times the first.  What are the two numbers?\r<BR>\n" );
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document.write( "Answer:  <BR>\n" );
document.write( "	One number is  <BR>\n" );
document.write( "	And the other number is  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58581 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=first number<BR>\n" );
document.write( "then 3x-1=second number\r<BR>\n" );
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document.write( "Now we are told that:\r<BR>\n" );
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document.write( "(3x-1)-x=47 get rid of parens\r<BR>\n" );
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document.write( "3x-1-x=47  add 1 to both sides\r<BR>\n" );
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document.write( "3x-1+1-x=47+1  collect like terms\r<BR>\n" );
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document.write( "2x=48  divide both sides by 2\r<BR>\n" );
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document.write( "x=24  -------------------------------the first number\r<BR>\n" );
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document.write( "3x-1=3(24)-1=72-1=71----------------------------second number\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "71-24=47<BR>\n" );
document.write( "47=47\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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