document.write( "Question 958429: find three consecutive integers such that the square of the smallest increased by four times the largest is five. \n" ); document.write( "
Algebra.Com's Answer #585755 by Theo(13342)\"\" \"About 
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your smallest number is x
\n" ); document.write( "your next smallest number is x + 1
\n" ); document.write( "your largest number is x + 2\r
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\n" ); document.write( "\n" ); document.write( "the square of the smallest increased by 4 times the largest is equal to 5 means:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 4 * (x + 2) = 5\r
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\n" ); document.write( "\n" ); document.write( "x is the smallest.
\n" ); document.write( "x + 2 is the largest.\r
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\n" ); document.write( "\n" ); document.write( "simplify this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 4x + 8 = 5\r
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\n" ); document.write( "\n" ); document.write( "subtract 5 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 4x + 3 = 0\r
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\n" ); document.write( "\n" ); document.write( "factor this quadratic equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x = -3
\n" ); document.write( "x = 1\r
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\n" ); document.write( "\n" ); document.write( "both of those values of x will satisfy the requirements of the problem.\r
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\n" ); document.write( "\n" ); document.write( "when x = -3, x + 2 = -1.\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 4 * (x + 2) becomes (-3)^2 + 4 * (-1) which becomes 9 - 4 which becomes 5.\r
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\n" ); document.write( "\n" ); document.write( "when x = -1, x + 2 = 1.\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 4 * (x + 2) becomes (-1)^2 + 4 * (1) which becomes 1 + 4 which becomes 5.\r
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\n" ); document.write( "\n" ); document.write( "both x = -3 and x = -1 satisfy the requirements of the problems.\r
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\n" ); document.write( "\n" ); document.write( "they are your solutions.\r
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