document.write( "Question 958270: Use Gauss-Jordan elimination to solve the following system of equations.
\n" ); document.write( "x+y+z=2
\n" ); document.write( "2x-3y+z=-11
\n" ); document.write( "-x+2y-z=8
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Algebra.Com's Answer #585647 by LinnW(1048)\"\" \"About 
You can put this solution on YOUR website!
The beginning matrix is\r
\n" ); document.write( "\n" ); document.write( "1 1 1 2
\n" ); document.write( "2 -3 1 -11
\n" ); document.write( "-1 2 -1 8\r
\n" ); document.write( "\n" ); document.write( "add 1 times the 1st row to the 3rd row
\n" ); document.write( "1 1 1 2
\n" ); document.write( "2 -3 1 -11
\n" ); document.write( "0 3 0 10\r
\n" ); document.write( "\n" ); document.write( "add -2 times the 1st row to the 2nd row
\n" ); document.write( "1 1 1 2
\n" ); document.write( "2 -5 -1 -15
\n" ); document.write( "0 3 0 10\r
\n" ); document.write( "\n" ); document.write( "add 3/5 times the 2nd row to the 3rd row
\n" ); document.write( "1 1 1 2
\n" ); document.write( "0 -5 -1 -15
\n" ); document.write( "0 0 -3/5 1\r
\n" ); document.write( "\n" ); document.write( "multiply the 3rd row by -5/3
\n" ); document.write( "1 1 1 2
\n" ); document.write( "0 -5 -1 -15
\n" ); document.write( "0 0 1 -5/3\r
\n" ); document.write( "\n" ); document.write( "add -1 times the 3rd row to the 1st row
\n" ); document.write( "1 1 0 11/3
\n" ); document.write( "0 -5 -1 -15
\n" ); document.write( "0 0 1 -5/3\r
\n" ); document.write( "\n" ); document.write( "add -1 times the 3rd row to the 2nd row
\n" ); document.write( "1 1 0 11/3
\n" ); document.write( "0 -5 0 -50/3
\n" ); document.write( "0 0 1 -5/3\r
\n" ); document.write( "\n" ); document.write( "multiply the 2nd row by -1/5
\n" ); document.write( "1 1 0 11/3
\n" ); document.write( "0 -5 0 -50/3
\n" ); document.write( "0 0 1 -5/3\r
\n" ); document.write( "\n" ); document.write( "add 1 times the 3rd row to the 2nd row
\n" ); document.write( "1 1 0 11/3
\n" ); document.write( "0 1 0 10/3
\n" ); document.write( "0 0 1 -5/3\r
\n" ); document.write( "\n" ); document.write( "add -1 times the 2nd row to the 1st row
\n" ); document.write( "1 0 0 1/3
\n" ); document.write( "0 1 0 10/3
\n" ); document.write( "0 0 1 -5/3\r
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