document.write( "Question 958248: Determine the probability distribution of the sums of rolling two dice \n" ); document.write( "

Algebra.Com's Answer #585629 by Fombitz(32388) $\"\"$ $\"About$

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There are 36 possible outcomes,
\n" ); document.write( "1,1 1,2 1,3 1,4 1,5 1,6
\n" ); document.write( "2,1 2,2 2,3 2,4 2,5 2,6
\n" ); document.write( "3,1 3,2 3,3 3,4 3,5 3,6
\n" ); document.write( "4,1 4,2 4,3 4,4 4,5 4,6
\n" ); document.write( "5,1 5,2 5,3 5,4 5,5 5,6
\n" ); document.write( "6,1 6,2 6,3 6,4 6,5 6,6
\n" ); document.write( "Look at the sums,
\n" ); document.write( "2 3 4 5 6 7
\n" ); document.write( "3 4 5 6 7 8
\n" ); document.write( "4 5 6 7 8 9
\n" ); document.write( "5 6 7 8 9 10
\n" ); document.write( "6 7 8 9 10 11
\n" ); document.write( "7 8 9 10 11 12
\n" ); document.write( "Then count the occurences of each sum,
\n" ); document.write( "2,1
\n" ); document.write( "3,2
\n" ); document.write( "4,3
\n" ); document.write( "5,4
\n" ); document.write( "6,5
\n" ); document.write( "7,6
\n" ); document.write( "8,5
\n" ); document.write( "9,4
\n" ); document.write( "10,3
\n" ); document.write( "11,2
\n" ); document.write( "12,1
\n" ); document.write( "Then divide by the total number of outcomes to get the probabilities,
\n" ); document.write( "2,1/36
\n" ); document.write( "3,2/36=1/18
\n" ); document.write( "4,3/36=1/12
\n" ); document.write( "5,4/36=1/9
\n" ); document.write( "6,5/36
\n" ); document.write( "7,6/36=1/6
\n" ); document.write( "8,5/36
\n" ); document.write( "9,4/36=1/9
\n" ); document.write( "10,3/36=1/12
\n" ); document.write( "11,2/36=1/18
\n" ); document.write( "12,1/36 \n" ); document.write( "

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