document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958237>Question 958237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The South Memorial School is designing a new playground. There will be a walkway that diagnolly crosses the square playground. The walkway is 55 meters long. Include a sketch of the playground and find the lenght of one side. Round your answer to the nearest 10th.\r<BR>\n" );
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document.write( "That's my problem but I can't solve, I don't think it provides enough information. Any one know what to do? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585620 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are dealing with a very special triangle, it's called an isosceles right triangle because it has two sides of the same length and two 45 degree angles.<BR>\n" );
document.write( "Did you sketch it like the problem asks you to? I did, see below.<BR>\n" );
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document.write( "Isosceles right triangles have a special relationship among the sides, 1:1:sqrt2 and one way to find the sides is using the \"pattern formula\", which applies ONLY to these special triangles:<BR>\n" );
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document.write( "Hypotenuse= Leg*sqrt2 <BR>\n" );
document.write( "But since we want to know the Legs, we divide both sides by sqrt2 and have: <BR>\n" );
document.write( "L= H/sqrt2= 1/2H*sqrt2. Since our hypotenuse is 55:<BR>\n" );
document.write( "L= 1/2*55*sqrt2= (55*1)/2*sqrt2= 27.5*sqrt2 <BR>\n" );
document.write( "The square root of 2 is 1.414, so multiply: <BR>\n" );
document.write( "27.5*1.414= 38.9 is the length of each side.<BR>\n" );
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document.write( "You can also solve it applying trigonometry, remember SOHCAHTOA. Since we know the hypotenuse, let's use CAH (Cosine Adjacent Hypotenuse):<BR>\n" );
document.write( "Cos45= L/55 Let's flip the equation, it will look better:<BR>\n" );
document.write( "L/55= Cos45 Calculate the cosine of 45 (your calculator):<BR>\n" );
document.write( "L/55= 0.707 Multiply both sides times 55<BR>\n" );
document.write( "L= 38.9 Oh, what a surprise, we got the same answer both ways ;-)<BR>\n" );
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