document.write( "Question 958250: Bob gave 2/3 of his chips and had 21chips left. How many chips did he give away?\r
\n" ); document.write( "\n" ); document.write( "I came up with 14 by doing 2/3*21
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Algebra.Com's Answer #585618 by Fombitz(32388)\"\" \"About 
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No.
\n" ); document.write( "He gave away 2/3 so he had 1/3 left.
\n" ); document.write( "So,
\n" ); document.write( "\"%281%2F3%29X=21\"
\n" ); document.write( "where X is the original amount he started with.
\n" ); document.write( "You can multiply both sides by 2.
\n" ); document.write( "\"%282%2F3%29X=42\"
\n" ); document.write( "So he had gave away 42 chips.\r
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