document.write( "Question 958229: 2 PLANES HAVE LEFT THE LA AIRPORT. ONE PLANE IS 70 MILES WEST OF THE AIRPORT AND HAS AN ALTITUDE OF 8 MILES. WHILE THE OTHER PLANE IS 20 MILES EAST OF THE AIRPORT AND HAS AN ALTITUDE OF 2 MILES. WHAT IS THE DISTANCE BETWEEN PLANES? \n" ); document.write( "

Algebra.Com's Answer #585608 by LinnW(1048) $\"\"$ $\"About$

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along the ground, the distance to points below each plane is 70 + 20 , or 90 miles.
\n" ); document.write( "Since one plane is 2 miles high and the other is 8 miles high, the distance between the planes is the hypotenuse of a triangle with height of 6 miles
\n" ); document.write( "and a base of 90 miles.
\n" ); document.write( "If c is the distance between the planes,
\n" ); document.write( " $\"c%5E2+=+90%5E2+%2B+6%5E2\"$
\n" ); document.write( " $\"c%5E2+=+8100+%2B+36\"$
\n" ); document.write( " $\"c+=+sqrt%288136%29\"$
\n" ); document.write( "c = 90.199 miles \n" ); document.write( "

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