document.write( "Question 958204: One year ago, Gill was five times as old as her horse. In one year’s time, the sum of their ages will be 22 . How old was Gill three years ago? \n" ); document.write( "
Algebra.Com's Answer #585589 by macston(5194)![]() ![]() You can put this solution on YOUR website! G=Gill's age; H=horse's age \n" ); document.write( "G+1yr+H+1yr=22yrs \n" ); document.write( "G+H+2yrs=22yrs \n" ); document.write( "G+H=20yrs \n" ); document.write( "G=20yrs-H \n" ); document.write( "G-1yr=5(H-1yr) Substitute for G \n" ); document.write( "(20yrs-H)-1yr=5H-5yrs \n" ); document.write( "19yrs-H=5H-5yrs Add 5yrs+H to each side \n" ); document.write( "24yrs=6H Divide each side by 6. \n" ); document.write( "4yrs=H The horse is 4 years old. \n" ); document.write( "G=20yrs-H=20yrs-4yrs=16yrs Gill is 16 years old \n" ); document.write( "G-3yrs=16yrs-3yrs=13yrs ANSWER: Three years ago, Gill was thirteen years old. \n" ); document.write( " |