document.write( "Question 81733: Solve the system by substitution.
\n" ); document.write( " 4x – 4y = –4
\n" ); document.write( " y = 2x + 0\r
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Algebra.Com's Answer #58558 by rapaljer(4671)\"\" \"About 
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4x – 4y = –4
\n" ); document.write( "y = 2x + 0\r
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\n" ); document.write( "\n" ); document.write( "Since the second equation is in the form y =___, it will be convenient to substitute this back into the first equation!\r
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\n" ); document.write( "\n" ); document.write( "4x - 4y = -4
\n" ); document.write( "4x-4(2x) = -4
\n" ); document.write( "4x - 8x = -4
\n" ); document.write( "-4x = -4
\n" ); document.write( "x=1\r
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\n" ); document.write( "\n" ); document.write( "Now, substitute this into either equation. The easiest was is to use the y = __ equation.\r
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\n" ); document.write( "\n" ); document.write( "y=2x
\n" ); document.write( "y=2(1)
\n" ); document.write( "y=2\r
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\n" ); document.write( "\n" ); document.write( "The solution is (1,2).\r
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\n" ); document.write( "\n" ); document.write( "Check in the OTHER equation:
\n" ); document.write( "4x-4y =-4
\n" ); document.write( "4(1)-4(2)=-4
\n" ); document.write( "4-8=-4 It checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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