document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958184>Question 958184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A has a speed of 15 miles per hour greater than that of train B.  If train A travels 195 miles in the same amount of time that train B travels 150 miles, what are the speeds of those two trains? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585573 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=rate of Train B; r+15mph=rate of Train A<BR>\n" );
document.write( "195mi/r+15=150mi/r Multiply by(r)(r+15mph)<BR>\n" );
document.write( "195mi(r)=150mi(r+15mph)<BR>\n" );
document.write( "195r mi=150r mi+150(15) mi^2/hr  Subtract 150r mi from each side<BR>\n" );
document.write( "45r mi=2250 mi^2/hr Divide each side by 45 mi<BR>\n" );
document.write( "r=50 mi/hr ANSWER 1: Train B's rate was 50 miles per hour.<BR>\n" );
document.write( "R+15mph=50mph+15mph=65 mph ANSWER 2: Train A's rate was 65 miles per hour.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "195mi/65mph=150mi/50mph<BR>\n" );
document.write( "3hrs=3hrs<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );