document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=958177>Question 958177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the range of y=3x+2 if the domain is {-3,-1,0,1,3}? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585571 by </B><A HREF=/tutors/aboutme.mpl?userid=arodr172><B>arodr172(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arodr172><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this, you have to plug-in each value of the domain to see what the y values are. The result of all your y values is the set of the range. \r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = 3x + 2 if the domain is {-3,-1,0,1,3}\r<BR>\n" );
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document.write( "Solution:\r<BR>\n" );
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document.write( "y = 3(-3) + 2 => -9 + 2 = -7 \r<BR>\n" );
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document.write( "y = 3(-1) + 2 => -3 + 2 = -1\r<BR>\n" );
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document.write( "y = 3(0) + 0 = 0\r<BR>\n" );
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document.write( "y = 3(1) + 2 = 5\r<BR>\n" );
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document.write( "y = 3(3) + 2 = 11\r<BR>\n" );
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document.write( "Therefore, the range is the set of all the y values {-7, -1, 0, 5, 11}. </SPAN>\n" );
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