document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81720>Question 81720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by addition.<BR>\n" );
document.write( "	x + y = 6<BR>\n" );
document.write( "	x – y = 4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58553 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just add the two equations together:\r<BR>\n" );
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document.write( "x + y = 6<BR>\n" );
document.write( "x – y = 4\r<BR>\n" );
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document.write( "2x=10<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "Now, substitute this value of x back into either equation (the first one will do!)\r<BR>\n" );
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document.write( "x+y=6<BR>\n" );
document.write( "5+y=6<BR>\n" );
document.write( "y=1\r<BR>\n" );
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document.write( "Check by substituting both numbers into the second equation:<BR>\n" );
document.write( "x-y=4<BR>\n" );
document.write( "5-1=4  It checks!!\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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