document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81714>Question 81714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given g(x) = 3x – 3, find g(2a).\r<BR>\n" );
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document.write( "Answer:  g(2a) =<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58547 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given g(x) = 3x – 3, find g(2a).<BR>\n" );
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document.write( "g(2a)  means to replace the x with 2a.\r<BR>\n" );
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document.write( "g(x) = 3x -3<BR>\n" );
document.write( "g(2a) = 3(2a) - 3<BR>\n" );
document.write( "g(2a) = 6a -3\r<BR>\n" );
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document.write( "R^2 at SCC\r<BR>\n" );
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