document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957922>Question 957922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the supplement of 42 degrees 20'<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585448 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 180°-42°20'=137°40' ANSWER The supplement is 137°40' </SPAN>\n" );
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